Pilot pulls record-setting 9.6Gs in Red Bull Air Race
BackMike Mangold's winning run at the 2007 Red Bull Air Race in Istanbul.
Channel: Sports
Uploaded: September 19, 2007 at 2:07 am
Author: redbullusa
Length: 00:01:46
Rating: 4.91
Views: 223399
Tags: air race airrace record flight flying crash speed red bull redbull stunt plane airplane g force gforce zivko
Video Comments:
skipplet (November 11, 2008 at 12:48 am)
Actually, teooo is right. After being selected to fly certain fighters, your G-tolerance is tested at the Holloman AFB centrifuge. One of the profiles includes a test of 9.0g for 15 seconds.
BlastedNation (November 4, 2008 at 11:59 pm)
By saying that 9G is your weight nine times...matematicaly youre sayng 9G=9x50pounds for example, thats obviously not right did you get my point?
thefullmonte03 (November 9, 2008 at 8:18 pm)
That's exactly correct. The statement is that weight=(mass)(acceleration acting on you)=m(g+a). where g is the acceleration due to gravity, and a is the centripetal acceleration due to the turn. You literally WEIGH 9 times as much as you do at rest.
skipplet (November 11, 2008 at 12:40 am)
BlastedNation you're a tard.
BlastedNation (November 3, 2008 at 8:03 pm)
forget that, 9G's is just 9 times the gravity acceleration, 9,8m/s. It has nothing to do with the weight, they say so so everybody can understand what G-force is.
RichTheBlack (November 4, 2008 at 1:09 pm)
Really,
weight is Mass x Acceleration, it is a measurement of the gravitational force acting on an object.
Near the surface of the Earth, the acceleration due to gravity is approximately constant; this means that an object's weight is roughly proportional to its mass.
The value given is what they would weigh at a nominal standard gravitational acceleration of 9.80665 m/s2.
So if you pull 9G's your weight IS 9 times greater.
weight is Mass x Acceleration, it is a measurement of the gravitational force acting on an object.
Near the surface of the Earth, the acceleration due to gravity is approximately constant; this means that an object's weight is roughly proportional to its mass.
The value given is what they would weigh at a nominal standard gravitational acceleration of 9.80665 m/s2.
So if you pull 9G's your weight IS 9 times greater.
BlastedNation (November 4, 2008 at 11:52 pm)
That is not my point, my point is that is not correct to say "8G is 8times body weight", of course it can be understood in that way but isnt the "right" definition of G.
thefullmonte03 (November 9, 2008 at 8:25 pm)
the added acceleration is not GRAVITY pulling any harder on you. Anytime you turn, you have a centripetal acceleration directed towards the center of the circle (your turn). It is not that g is 9 times is origrinal value, it is that (acceleration due to gravity (g)) + (centripetal acceleration due to the turn (8g)) = 9g.
Since weight=m*a(total), then w=m*9g, and weight is 9 times its original value
Since weight=m*a(total), then w=m*9g, and weight is 9 times its original value
Navinajr (November 2, 2008 at 6:57 pm)
check out mike goulian, also an incredible pilot. His airshows are amazing.
MetsNY5715 (October 30, 2008 at 9:48 pm)
No problem deutsche bag.
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